# Math Rendering Test Case

## Inline Math

This is Inline Math using `\( ... \)` \( x + y = z \in \left\{ -1, 1 \right\} \) and now using `$ ... $` $ x + y = z \in \left\{ -1, 1 \right\} $ and it should handle the case of giving my friend 2\$.  

We can also do the same without gaps.

This is Inline Math using `\(...\)` \(x + y = z \in \left\{ -1, 1 \right\}\) and now using `$...$` $x + y = z \in \left\{ -1, 1 \right\}$ and it should handle the case of giving my friend 2\$.  

It can also take care of cases of one sided gaps.

This is Inline Math using `\( ...\)` \( x + y = z \in \left\{ -1, 1 \right\}\) and now using `$ ...$` $ x + y = z \in \left\{ -1, 1 \right\}$ and it should handle the case of giving my friend 2\$.  

This is Inline Math using `\(... \)` \(x + y = z \in \left\{ -1, 1 \right\} \) and now using `$... $` $x + y = z \in \left\{ -1, 1 \right\} $ and it should handle the case of giving my friend 2\$. 

Here is a dollar test. My friend has \$2.00 and I have \$10.00. $ 2 + 10 = 13 $.

## Display Math

Well, this should be less challenging:

\[ x + y = z \in \left\{ -1, 1 \right\} \] 

\[x + y = z \in \left\{ -1, 1 \right\}\] 

\[ x + y = z \in \left\{ -1, 1 \right\}\] 

\[x + y = z \in \left\{ -1, 1 \right\} \] 

$$ x + y = z \in \left\{ -1, 1 \right\} $$

$$x + y = z \in \left\{ -1, 1 \right\}$$

$$ x + y = z \in \left\{ -1, 1 \right\}$$

$$x + y = z \in \left\{ -1, 1 \right\} $$

## Environments

\begin{align*}
x + y & = z \in \left\{ -1, 1 \right\} \\
g + h & = l
\end{align*}

$$ \begin{align*}
x + y & = z \in \left\{ -1, 1 \right\} \\
g + h & = l
\end{align*} $$

$$ \begin{align*}
x + y & = z \in \left\{ -1, 1 \right\} \\
g + h & = l
\end{align*}$$

$$\begin{align*}
x + y & = z \in \left\{ -1, 1 \right\} \\
g + h & = l
\end{align*} $$

\begin{align*} x + y & = z \in \left\{ -1, 1 \right\} \\ g + h & = l \end{align*}

\begin{align*}x + y & = z \in \left\{ -1, 1 \right\} \\ g + h & = l\end{align*}

\begin{align*} x + y & = z \in \left\{ -1, 1 \right\} \\ g + h & = l\end{align*}

\begin{align*}x + y & = z \in \left\{ -1, 1 \right\} \\ g + h & = l \end{align*}

$$\begin{align*}x + y & = z \in \left\{ -1, 1 \right\} \\ g + h & = l\end{align*}$$

$$ \begin{align*}x + y & = z \in \left\{ -1, 1 \right\} \\ g + h & = l\end{align*} $$

<script type="text/x-mathjax-config">
MathJax.Hub.Config({
    config: ["MMLorHTML.js"],
    jax: ["input/TeX", "output/HTML-CSS", "output/NativeMML"],
    extensions: ["tex2jax.js", "MathMenu.js", "MathZoom.js"],
    tex2jax: {
        inlineMath: [ ["\\(","\\)"] ],
        displayMath: [ ["\\[","\\]"] ]
    },
    displayAlign: 'left',
    showProcessingMessages: false,
    messageStyle: 'none'
});
</script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/mathjax/2.7.0/MathJax.js"></script>
